Question

Find the value of k.
x square-5x+3(k-1)=0 is 11

Answer 1

Answer:

Only put value of x in eq

X^2-5x+3(k-1)=0

(11)^2-5(11)+3(k-1)=0

121-55+3k-3=0

66+3k-3=0

63+3k=0

-63=3k

K=-63÷3

K=-21