Question

find the value of k x2+5kx+16=0 has real and equal root
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Answer 1

Answer: k is + or - 2

Step-by-step explanation:

We know for real and equal roots,

b^2-4ac = 0

Or, (4k)^2 - 4×1×16 = 0

Or, 16k^2 = 4×16

Or, k^2 = 4

Or, k = +/- 2

So, the CORRECT ANSWER IS +/- 2.

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Answer 2

Answer:

kx^2 + 5kx + 16 = 0

Comparing with ax^2 + bx + c = 0

we get a=k, b=5k, c=16

The equation has real and equal roots.

Therefore, b^2-4ac=0

(5k) ^2 - 4(k) (16) = 0

25k^2 - 64k = 0

25k^2 = 64k

25 × k × k = 64 × k

k = 64 × k

25 × k

k = 64/25

The answer is 64/25.

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