Find the value of k, y-1 is the zero of the polynomial 3x square +5x+h
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the ques would be like this
3y^2+5y+k
answer:
y-1=0
y=1
substitute this in the equation
3(1)^2+5(1)+k=0
9+5+k=0
14+k=0
k= -14
here is your answer
hope it helps
mark as brainliest plz!!!!
3y^2+5y+k
answer:
y-1=0
y=1
substitute this in the equation
3(1)^2+5(1)+k=0
9+5+k=0
14+k=0
k= -14
here is your answer
hope it helps
mark as brainliest plz!!!!
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