Question

find the value of k , y+3 is a factor of 3y² +ky + 6

Answer 1

Hey

Here is your Answer

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Step-by-step explanation:

If y+3 is a factor of the given polynomial 3y^2 + my + 6 = 0,

y + 3 = 0

Therefore y = -3

Now , substitute the value of y in the given polynomial,

3(-3)^2 + (-3)k + 6 = 0

We equate the equation to zero, because the substitution of the factor always gives the value 0.

When solving the equation ,

27 - 3k + 6 = 0

3k = 33

K = 33/3

K = 11

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Hope it helps you!I

Answer 2

Solution :

If y+3 is a factor of the given polynomial 3y^2 + my + 6 = 0

→ y + 3 = 0

→ y = -3

Now , substitute the value of y in the given polynomial,

→ 3y² + ky + 6

→ 3(-3)² + (-3)k + 6 = 0

We equate the equation to zero, because the substitution of the factor always gives the value 0

When solving the equation ,

→ 27 - 3k + 6 = 0

→ 3k = 33

→ K = 33/3

→ K = 11