Question

Find the value of kx2 - 14x + 8 = 0 if one of the root is six times the other.

Answer 1

solution:

if 1st zero is alpha(a)

so,2nd zero will 6 alpha(a)

sum of zero = -b/a

a+6a= -(-14)/k

7a =14/k

a=14/7k..........eq1

product of zero = c/a

a×6a=8/k

6a² = 8/k

now put the value of from 1st eq and solve it answer will come