Question

find the value of kxsquare - kx + 1 = 0 has equal roots.

Answer 1

$kx {}^{2} - kx + 1 = 0 \\ b {}^{2} - 4ac = 0 \\ k {}^{2} - 4(k)(1) = 0 \\ k {}^{2} - 4k = 0 \\ k(k - 4) = 0 \\ k = 0 \: and \: k = 4$

Answer 2

k^2-kx+1
b^2-4ac=0
(-k)^2-4k=0
k^2-4k=0
k*(k-4)=0
k-4=0
k=4 answer