Question

find the value of L0g16 - Log 2 (take base2)​

Answer 1

Step-by-step explanation:

$log_{2}16 - log_{2}2 = log_{2}(2) {}^{4} - 1$

$4log_22 \div 1$=4

answer is =4.

formula:-{loga =1} {loga-log b=log a/logb}