Find the value of lambda for which x is equal to under root 2 is a solution of the quadratic equation lambda x square + root 2 x minus 4 is equal to zero
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Answer:
2
Step-by-step explanation:
Please read ¥ as lambda
¥x²+√2x-4=0
put the value of x=√2 (given that √2 is a solution)
¥(√2)²+√2(√2)-4=0
2¥+2-4=0
2¥=2
¥=2
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