Question

find the value of latent heat of fusion of ice in kj/kg. given : the latent heat of fusion of ice is 80cal/g​

Answer 1

Answer:

3.36 x 10*5 j = 336 kj

Explanation:

1 cal = 4.2 j      

80 x 4.2 x 10 *3 = 336 kj