Find the value of lettered angels in this figure
Answers
Answer:
x = 36, y = 56
Step-by-step explanation:
In triagle ABC given AB = AC ten Angle B = Angle C we get
x + 2x+2x = 180 ( sum of angles in a triangle)
5x = 180
then x = 36
In triangle ADC we get A+ D+C = 180
given AB parallel to DC then Angle BAC = Angle ACD
so we get angle x + 88 + y = 180
36 +88+ y = 180
then y = 56
Answer:
X = 36
Y = 56
Step-by-step explanation:
Note: (x) = angle x
In Triangle ABC
(A) + (B) + (C) = 180 ----( sum of angles of a triangle)
Also, (B) = (C) ----- ( isosceles triangle)
(C) = (B) = 2x
Now,
2x + 2x + x = 180
5x = 180
x = 36
Now in Triangle ADC
(A) + (D ) + (C) = 180
y + 88 + (C) = 180
(C) = 92 - y
Now when AB is parallel to DC and AC is the transversal
(A) = (C) ----- ( alternate interior angle)
(C) = x = 36
So,
36 = 92 - y
y = 56
We can by adding all angles their sum will be 360 which is the sum of angles of quadrilateral
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