Math, asked by HeerNayak, 9 months ago

Find the value of lettered angels in this figure​

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Answers

Answered by vipulsaibewar
1

Answer:

x = 36, y = 56

Step-by-step explanation:

In triagle ABC  given AB = AC ten Angle B =  Angle C we get

x + 2x+2x = 180 ( sum of angles in a triangle)

5x = 180

then x = 36

In triangle ADC we get A+ D+C = 180

given AB parallel to DC then Angle BAC = Angle ACD

so we get angle x + 88 + y = 180

36 +88+ y = 180

then y = 56

Answered by Sambhav0720
1

Answer:

X = 36

Y = 56

Step-by-step explanation:

Note: (x) = angle x

In Triangle ABC

(A) + (B) + (C) = 180 ----( sum of angles of a triangle)

Also, (B) = (C) ----- ( isosceles triangle)

(C) = (B) = 2x

Now,

2x + 2x + x = 180

5x = 180

x = 36

Now in Triangle ADC

(A) + (D ) + (C) = 180

y + 88 + (C) = 180

(C) = 92 - y

Now when AB is parallel to DC and AC is the transversal

(A) = (C) ----- ( alternate interior angle)

(C) = x = 36

So,

36 = 92 - y

y = 56

We can by adding all angles their sum will be 360 which is the sum of angles of quadrilateral

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