Math, asked by ppriyanshu382, 5 months ago

Find the value of log (1/2401) to the base 7​

Answers

Answered by tennetiraj86
0

Answer:

answer for the given problem is 4

Attachments:
Answered by pulakmath007
0

\displaystyle \sf{  log_{7} \bigg(  \frac{1}{2401} \bigg)  } =  - 4

Given :

\displaystyle \sf{  log_{7} \bigg(  \frac{1}{2401} \bigg)  }

To find :

The value of the expression

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

\displaystyle \sf{  log_{7} \bigg(  \frac{1}{2401} \bigg)  }

Step 2 of 2 :

Find the value of the expression

\displaystyle \sf{  log_{7} \bigg(  \frac{1}{2401} \bigg)  }

\displaystyle \sf{  =  log_{7} \: 1 -  log_{7} \: 2401  }

\displaystyle \sf{  =  0 -  log_{7} \: (7 \times 7 \times 7 \times 7)  }

\displaystyle \sf{  =   -  log_{7} \: ( {7}^{4} )  }

\displaystyle \sf{  =   - 4 log_{7} \: 7  }

\displaystyle \sf{  =   -  4 \times 1 }

\displaystyle \sf{  =   -  4}

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