find the value of log 12 base 3 into log 72 base 3 - log 192 base 3 into log 6 base 3
Answers
Answered by
23
The Question is,
log₃12 * log₃72 - log₃192 * log₃6 = ?
= (log₃ 3 + 2log₃ 2)( 2log₃3 + 3log₃2) - ( log₃3+ 6log₃2)( log₃3 + log₃2)
= (1 + 2log₃2)(2+ 3log₃2) - (1+6log₃2)(1+log₃2)
= 1
so, all this is reduced to 1, Thus 1 is the answer
log₃12 * log₃72 - log₃192 * log₃6 = ?
= (log₃ 3 + 2log₃ 2)( 2log₃3 + 3log₃2) - ( log₃3+ 6log₃2)( log₃3 + log₃2)
= (1 + 2log₃2)(2+ 3log₃2) - (1+6log₃2)(1+log₃2)
= 1
so, all this is reduced to 1, Thus 1 is the answer
Answered by
2
Answer:
Here the following property of log is used:-
Log(MN)=logM+logN
Attachments:
Similar questions