Question

Find the value of log 128 to the base √2?​

Answer 1

Answer:

Step-by-step explanation:

We know,

sqrt(2)=2^(1/2)

128=2^7

Thus,

log  (base √2) 128

=log(base 2^1/2) 2/7

=7*2 log (base 2) 2 [as log (base b^n) a^m=m/n log (base b) a]

=14 (Ans)