Find the value of log(165/125) to the base 4/5 +log1to the base 4/5
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log(165/125) to the base (4/5)
= log(31/25) to the base (4/5)
and it can also be written as
[ log 31 - log 25 ]
both to the base (4/5).
Now log(1) to the base any natural number (as in this case 4/5) is always zero.
so adding both will give:
= (log 31 - log 25)
or
log (31/25)
both to the base of (4/5)
= log(31/25) to the base (4/5)
and it can also be written as
[ log 31 - log 25 ]
both to the base (4/5).
Now log(1) to the base any natural number (as in this case 4/5) is always zero.
so adding both will give:
= (log 31 - log 25)
or
log (31/25)
both to the base of (4/5)
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