Question

find the value of log 2/5(32/3125)​

Answer 1

Step-by-step explanation:

use logarithm concept ,

when, argument and base are same elements then log =1

e.g xlog (a base a) = x

now,

given,

log(32/3125 base 2/5 )

you know ,

2^5 = 32

5^5 = 3125

hence ,

32/3125 = (2/5)^5

so, log{ (2/5)^5 base 2/5 }

= 5log ( 2/5 base 2/5)

=5