Find the value
of log√2 base 7 if log
2 = .3010 and log7 =
.4950
Answers
Answered by
0
Answer:
0.3040
Step-by-step explanation:
log 10 (2) = 0.3010
log 10 (7) = 0.4950
log 7 (_/2)
[ log a (b) = log 10 (b) / log 10 (a) ]
log 7 (_/2) = log 10 ( 2^0.5) / log 10 (7)
[ log a (b^x) = x log a (b) ]
log 7 (_/2) = 0.5 log 10 (2) / log 10 (7)
= 0.5 × 0.3010 / 0.4950
= 0.3040
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