Question

Find the value of log (225/32)-log (25/81)+log(64/729)

Answer 1

log2 will be answer log@+log#-log$
=log@#1/$

Answer 2

Answer:

The value of given expression is log 2.

Step-by-step explanation:

The given expression is

$log(\frac{225}{32})-log(\frac{25}{81})+log(\frac{64}{729})$

Using property: $loga-log b=log(\frac{a}{b})$

$log(\frac{225}{32}\times \frac{81}{25})+log(\frac{64}{729})$

Using property: $loga+log b=log(ab)$

$log(\frac{225}{32}\times \frac{81}{25}\times \frac{64}{729})$

Cancel out the common factors.

$log(2)$

Therefore the value of given expression is log 2.