find the value of log 25 to the base 8 given log 2= 0.3010 is
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Answered by
149
Identities used:
1. loga (b) = 1 / logb (a)
2. n*log x = log xn
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log8 (25) = log8 (100/4) = log8 (100) - log8(4)
log8 (102) - log8(4)
2*log8 (10) - log8(4)
Now log8(10) = 1/ log10(8), also log8(4) = 2/3
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2 / log10 (8) - 2/3
2 / log10 (23) - 2/3
2 / 3*log10 (2) - 2/3
2/ 3 x 0.3010 - 0.667
2/ 0.903 - 0.667
2.2148 - 0.667
= 1.548
1. loga (b) = 1 / logb (a)
2. n*log x = log xn
-
log8 (25) = log8 (100/4) = log8 (100) - log8(4)
log8 (102) - log8(4)
2*log8 (10) - log8(4)
Now log8(10) = 1/ log10(8), also log8(4) = 2/3
-
2 / log10 (8) - 2/3
2 / log10 (23) - 2/3
2 / 3*log10 (2) - 2/3
2/ 3 x 0.3010 - 0.667
2/ 0.903 - 0.667
2.2148 - 0.667
= 1.548
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5
Answer:
In logarithm we will practice different types of questions on how to solve logarithmic functions on log. Solved examples on logarithm will help us to understand each and every log rules and their applications. Solving logarithmic equation are explained here in details so that student can understand where it is necessary to use logarithm properties like product rule, quotient rule, power rule and base change rule
Step-by-step explanation:
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