Math, asked by tonyoo, 1 year ago

find the value of log 256 base root2

Answers

Answered by sharmilafareedp30hcc

6

log $log_{ \sqrt{2}$ 256

256= $(\sqrt{2} )^{16}$
⇒ log 256 to base root 2
is 16

sharmilafareedp30hcc: small mistake log is printed two times in first step sorry

sharmilafareedp30hcc: please mark my answer as brainliest if it helped you.

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