Question

Find the value of log 9^2002 ,if log 3 to base 10 = 0.477

Answer 1

Answer:

$log_{10}( {9}^{2002} ) = log_{10}( {3}^{4004 } ) = 4004 \times log_{10}(3) = 4004 \times 0.477 = 1909.908$