Question

Find the value of log12+log3-log27

Answer 1

Answer:

log12+log3-log27

=log(3×4)+(0.47712)-log3³

=log(3×2²)+(0.47712)-3log3

=log3+log2²+(0.47712)-3(0.47712)

=(0.47712)+2log2+(0.47712)-(1.43136)

=(0.47712)+2(0.30103)+(0.47712)-(1.43136)

=0.47712+0.60206+0.47712-1.43136

=1.55630-1.43136

=0.12494