Question

Find the value of log2(1/32).​

Answer 1

:

log

2(132)=log

2(125)

=log2(2−5)

=−5log2(2)

=−5⋅1

=−5

Answer 2

Answer:-

$log_{2}(\dfrac{1}{32}) = -5$

Explanation:-

To Find

The value of $log_{2}(\dfrac{1}{32})$

Solution

let,

$log_{2}(\dfrac{1}{32}) = x$

We know that

$log_{a}N = x \implies {a}^{x}= N$

on putting the values

$\implies {2}^{x}= \dfrac{1}{32}$

$\implies {2}^{x}= {(\dfrac{1}{2})}^{5}$

$\implies {2}^{x}= {2}^{-5}$

Here, bases are equal.. So, let us equate the powers!

$\implies x = -5$

$\therefore log_{2}(\dfrac{1}{32}) = -5$