Math, asked by SrijanShrivastava, 10 months ago

Find the value of :

log₂ [(2∛9 − 2).(12∛3 + 4 + 4∛9)]

Answer only if you know!
I want solution.

Answers

Answered by pokuruvam147

2

Answer:

log2(72⅓-8⅓)×(72⅔+8⅔+72⅓.8⅓)

log2(72+72⅓-8⅔+72⅔ 8⅓-72⅔.8⅔-8-72⅓.8⅔)

cancel the numbers which are positive and negative numbers

log2(72-8)

log2(64)

log2(2⁶)

6log2base2

=6

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