Math, asked by taqueerizwan2006, 2 months ago

Find the value of log₂ ( log₂ . log₃81 ) ....

Answers

Answered by anindyaadhikari13
10

Required Answer:-

Given to Evaluate:

  • log₂ [log₂(log₃81)]

Solution:

We have,

log₂[log₂(log₃81)]

= log₂[log₂(log₃ 3⁴)] [As 3⁴ = 81]

= log₂[log₂(4 × log₃(3))] [As log(x)ⁿ = n log(x)]

= log₂[log₂(4)] [3¹ = 1 So, log₃(3) = 1]

= log₂[log₂(2²)] [As 2² = 4]

= log₂[2 × log₂(2)] [As log(x)ⁿ = n log(x)]

= log₂[2] [On simplifying]

= 1 [2¹ = 2 So log₂(2) = 1]

Hence, the required answer is 1.

Answer:

  • On simplifying, we get the result 1.
Answered by XxMissCutiepiexX
9

Given to Evaluate:

log₂ [log₂(log₃81)]

Solution:

We have,

log₂[log₂(log₃81)]

= log₂[log₂(log₃ 3⁴)] [As 3⁴ = 81]

= log₂[log₂(4 × log₃(3))] [As log(x)ⁿ = n log(x)]

= log₂[log₂(4)] [3¹ = 1 So, log₃(3) = 1]

= log₂[log₂(2²)] [As 2² = 4]

= log₂[2 × log₂(2)] [As log(x)ⁿ = n log(x)]

= log₂[2] [On simplifying]

= 1 [2¹ = 2 So log₂(2) = 1]

Hence, the required answer is 1.

Answer:

On simplifying, we get the result 1.

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