Question

find the value of log4/3.log5/4.log6/5.log7/6.log8/7.log9/8

Answer 1

since logA.logB = log(A.B)
∴log(4/3).log(5/4).log(6/5).log(7/6).log(8/7).log(9/8)
=log[(4/3)×(5/4)×(6/5)×(7/6)×(8/7)×(9/8)]
=log3