find the value of log40 base 12
Answers
Answered by
0
Answer:
what is this something you would like
Step-by-step explanation:
what is this something you would like
Answered by
0
Step-by-step explanation:
= log40 base 12
from the formula, log a base b = log a /log b ( both base 10)
= log 40 / log 12
= log 4*10 / log 4*3
from the formula, log a*b = log a + log b
= (log 4 + log 10) / ( log 4 + log 3)
as we know log 10 base 10 = 1,
= (log 2² + 1 ) / ( log 2² + log 3)
from the formula, log a^b = b log a,
= (2 log2 + 1) / (2log2 + log3)
since log 2 base 10 = 0.3010
log 3 base 10 = 0.4771
= ((2* 0.3010) +1) / ( (2*0.3010) + 0.4771)
= (0.602+1)/ (0.602 +0.4771)
= 1.602/1.0791
= 1.485
Similar questions