Question

Find the value of log600 if log 2=0.3010 and log 3=0.4771

Answer 1

Answer:

log(600)=log(6*100)=log(6) + log(100)

=log2*3 + log10^2

=log2 + log3 +2log10 {log10=1}

And from question

=0.3010+0.4771+2

=2.7781

Step-by-step explanation:

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Answer 2

Answer:

2.7781

Step-by-step explanation

log600=log3*2*100

=log3+log2+log100

=0.4771+0.3010+2log10

=0.7781+2

=2.7781

Hope it helps you