Math, asked by ashimbanik99, 8 months ago


Find the value of
log8√4096

Answers

Answered by Anonymous
48

\large{\underline{\underline{\red{\bf{Answer:}}}}}

  • The required answer is 2.

\rule{200}4

\large{\underline{\underline{\red{\bf{Step\:by\:step\: explanation:}}}}}

{\underline{\underline{\purple{\bf{Given:}}}}}

  • A logarithm is given to us.
  • The logarithm is \sf{log_{8}^{\sqrt{4096}}}

{\underline{\underline{\purple{\bf{To\: Find:}}}}}

  • The value of the given logarithm.

{\underline{\underline{\purple{\bf{Answer:}}}}}

Taking the given logarithm ,

= \sf{log_{8}^{\sqrt{4096}}}

= \sf{ log_{8}^{\sqrt{64\times 64}}}

=  \sf{log _{8} ^{64}}

= \sf{log _{8} ^{8^2}}

= \sf{2\times log_{8}^{8}}

= \sf{2\times1}

=\bf{2}

Hence the required answer is 2.

\rule{200}2

{\underline{\underline{\purple{\bf{Some\:more\: information:}}}}}

There are two systems of logarithm ,

  • Natural logarithm
  • Common logarithm

{\orange{\bf{\leadsto Natural \: logarithms:}}}

  • These were introduced by Napier. They are calculated to the base e (Euler's number) , whose value is approximately equal to 2.7828. These are used in higher mathematics .

{\orange{\bf{\leadsto Common \: logarithms:}}}

  • The logarithms to the base 10 are called Common logarithms . This was introduced by Briggs , who was contemporary of Napier .

{\underline{\underline{\purple{\bf{\longmapsto Properties\:of\: logarithms:}}}}}

  • Logs are defined for positive bases only. (except 1).
  • It is defined for positive real numbers.
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