Question

Find the value of
(Loga)²-(logb)²

Answer 1

Answer:

Question is in the form of a^2 - b^2 so the formulae is

(a+b)(a-b)=a^2 - b^2 where a=loga,b=logb

substitue in the formulae we get

(loga+logb)(loga-logb)

(log(ab))(log(a/b))

Answer 2

Answer:

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