Question

Find the value of logy(x4) if logx(y3) = 2​

Answer 1

Answer: 6

Step-by-step explanation:

log(a^x) = 1/log(x^a) ---------------------1

 

log x(y^3)=3logx^y=2    ---------------------2

implies        log x^y=2/3   ------------------3

log y^x4=4logy^x    -----------------------4

log y^x=1/log x^y

4 log y^x = 4/log x^y

               =4/(2/3)

               

                =4*3/2

               

                 =6

hope this helps !

 

Answer 2

Answer:

㏒(y)($x^{4}$)=8-(11)㏒(y)

Step-by-step explanation:

consider

          ㏒ x($y^{3}$)=2

from identity

          ㏒(ab)=㏒(a)+㏒(b)

          ㏒x$y^{3}$=㏒(a)+㏒($y^{3}$)

we know that

          ㏒$y^{3}$=(3)㏒(y)

          ㏒x$y^{3}$=㏒(x)+(3)㏒(y)=2

          ㏒(x)=2-3㏒(y)

          ㏒(y)($x^{4}$)=㏒(y)+4㏒(x)

           ㏒(y)($x^{4}$)= ㏒(y)+4(2-(3)㏒(y))

           ㏒(y)($x^{4}$)= ㏒(y)+8-(12)㏒(y)

           ㏒(y)($x^{4}$)=8-(11)㏒(y)

The project code is #SPJ2