Question

Find the value of m ​

Answer 1

$( \frac{3}{5} ) {}^{2m} \times ( \frac{9}{25} ) {}^{3} = ( \frac{3}{5} ) {}^{ - 2}$

$( \frac{3}{5} ) {}^{2m} \times ( \frac{3}{5} ) {}^{(2)3} = ( \frac{3}{5} ) {}^{ - 2}$

$( \frac{3}{5} ) {}^{2m} \times ( \frac{3}{5} ) {}^{6} = ( \frac{3}{5} ) {}^{ - 2}$

Compare the powers

$2m + </em></strong><strong><em>6</em></strong><strong><em> = - 2$

$2m = - 2 - </em></strong><strong><em>6</em></strong><strong><em>$

$2m = - </em></strong><strong><em>4</em></strong><strong><em>$

$m = \frac{ - </em></strong><strong><em>4</em></strong><strong><em>}{2}$

m=-2

Answer 2

Answer:

The value of m is 4 for the given problem