Question

Find the value of m^3+n^3-p^3-3mnp, when m=4,n=-3 and p=2.

Answer 1

Answer:

-43

Step-by-step explanation:

${4}^{3} + { - 3}^{3} - {2}^{3} - (3 \times 4 \times 3 \times 2)$

= -43

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Answer 2

Answer:

The correct answer is 101

Step-by-step explanation:

Given problem

Find the value of  m³ + n³ - p³ -3mnp  _ (1)

when m = 4 , n = -3 and p = 2  

substitute  m = 4 , n = -3 and p = 2 in (1)

(1) ⇒ 4³ + (-3)³ - (2)³ - 3 (4) (-3) (2)  

   ⇒ 64 - 27 - 8 - [12(-6)]

   ⇒ 64 - 35 + 72

   ⇒ 101    

⇒ The value of m³+ n³- p³- 3mnp,  when m = 4, n = -3 and p = 2 is 101