Find the value of m and n
3x+4y=12
(m+n)x + 2(m-n)=5m-1
Provided the eqn has infinite solutions
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Answer:
If two linear equations have infinitely many solutions means
a1/a2 = b1/b2 = c1/c2
here two linear equations are
3x+4y=12 and (m+n)x + 2(m-n)y = (5m-1)
So we can write,
= =
From this we get, 3/(m+n) = 4/[2(m-n)]
6(m-n)=4(m+n)
6m - 6n = 4m -4n
2m - 10n = 0 --------------(1)
similarly 3/(m+n) = 12/(5m-1)
3m - 12n = 3 -------------------(2)
(1) ⇒ 6m - 30n=0 -------(3)
(2) ⇒ 6m - 24n = 6 ------(4)
(4) - (2) ⇒ 6n = 6
n = 1
substituting the value of n in (1)
then (1) becomes 2m - 10 =0
m=5
Therefore m= 5 and n=1
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