Question

Find the value of m and n so that the following system of linear equation have infinite number of solutions
(2m-1)x+3y-5=0
3x+(n-1)y-2=0

Answer 1

⚡Here is your answer⚡

a1/a2 = b1/b2 = c1/c2

(2m + 1)/3 = 3/(n-1)= -5/-2

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(1) (2) (3)

compare (1)and(3)

2m+1/3 = -5/-2

4m+2=15

4m=15-2

4m=13

m=13/4

from eq (2)and(3)

3/n-1=-5/-2

5n-5=6

5n=6+5

5n=11

n=11/5

⭐Mahir⭐

Answer 2

Step-by-step explanation:

(2m-1)x + 3y - 5 = 0

3x + (n-1)y - 2 = 0

There are infinite number of solutions

So , a1/a2 = b1/b2 = c1/c2

(2m-1) / 3 = 3 / (n-1) = 5/2

Equating 1 and 2

We have 4m - 2 = 15

4m = 17

m = 17/4

Equating 2 and 3

We have 5n - 5 = 6

5n = 11

n = 11/5