Question

Find the value of m and n so that the polynomial f(x)=x^3-6x^2+mx-n Is exactly divisible by (x-1) as well as (x-2).?

Answer 1

p(x)=x^3-6x^2+mx-n
put x=1
p(1)=(1)^3+-6(1)^2+m(1)-n
=-5+m-n
=-n=5-m....eq.1
put x=2
p(2)=(2)^3-6(2)^2+m(2)-n
by substituting value of -n and solving it we'll get m=11
now by using value of m in eq.1 we'll have
-n=-6
now by removing negative sign from both sides
n=6
thus it is your required solution
now you can mark my answer as brainliest ☺️

Answer 2

hii
this is your answer