Question

Find the value of m and n so that the polynomial f(x) = x3 – 6x2 + mx – n is exactly divisible by

(x –1) as well as (x – 2)​

Answer 1

Answer:

Hi,I hope this is helpful to you

If f(x) =x^3-6x^2+mx-n is exactly divisible by x-1

So x-1=0

x=1

f(1)=1^3-6(1)^2+m×1-n=0

=1-6+m-n=0

=-5+m-n=0

=m=n+5 ... (1)

If f(x) =x^3-6x^2+mx-n is exactly divisible by x-2

So x-2=0

x=2

f(2)=2^3-6(2)^2+m×2-n=0

=8-24+2m-n=0

=-16+2m-n=0

=2m-n=16 ... (2)

From eq 1&2

2(n+5)-n=16[m=n+5]

2n+10-n=16

n=16-10

n=6

Putting the value of n in eq 1

m=6+5

m=11

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