Question

find the value of m for (2m+1)x^2+2(m+3)x+(m+5)=0 where the roots are equal​

Answer 1

Answer:

Hey there,

Hey there,That's a good question. So let's start from the very beginning!!!

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0(2m-2)²-4(m+5)=0

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0(2m-2)²-4(m+5)=04m²-12m-16=0

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0(2m-2)²-4(m+5)=04m²-12m-16=0Taking 4 as common, we get-

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0(2m-2)²-4(m+5)=04m²-12m-16=0Taking 4 as common, we get-m²-3m-4=0

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0(2m-2)²-4(m+5)=04m²-12m-16=0Taking 4 as common, we get-m²-3m-4=0m²+4m-m-4=0

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0(2m-2)²-4(m+5)=04m²-12m-16=0Taking 4 as common, we get-m²-3m-4=0m²+4m-m-4=0m(m+4)-1(m+4)=0

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0(2m-2)²-4(m+5)=04m²-12m-16=0Taking 4 as common, we get-m²-3m-4=0m²+4m-m-4=0m(m+4)-1(m+4)=0(m-1)(m+4)=0

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0(2m-2)²-4(m+5)=04m²-12m-16=0Taking 4 as common, we get-m²-3m-4=0m²+4m-m-4=0m(m+4)-1(m+4)=0(m-1)(m+4)=0Therefore m=1 or m=-4

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0(2m-2)²-4(m+5)=04m²-12m-16=0Taking 4 as common, we get-m²-3m-4=0m²+4m-m-4=0m(m+4)-1(m+4)=0(m-1)(m+4)=0Therefore m=1 or m=-4PLEASE MARK AS BRAINLIEST IF HELPFUL!!!

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0(2m-2)²-4(m+5)=04m²-12m-16=0Taking 4 as common, we get-m²-3m-4=0m²+4m-m-4=0m(m+4)-1(m+4)=0(m-1)(m+4)=0Therefore m=1 or m=-4PLEASE MARK AS BRAINLIEST IF HELPFUL!!!Regards

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0(2m-2)²-4(m+5)=04m²-12m-16=0Taking 4 as common, we get-m²-3m-4=0m²+4m-m-4=0m(m+4)-1(m+4)=0(m-1)(m+4)=0Therefore m=1 or m=-4PLEASE MARK AS BRAINLIEST IF HELPFUL!!!Regards07161020

Hey there,That's a good question. So let's start from the very beginning!!!EQUATION-x²+x(2m-2)+(m+5)If the roots are to be real and equal then the value of discriminant(D) is to be 0.D=0(2m-2)²-4(m+5)=04m²-12m-16=0Taking 4 as common, we get-m²-3m-4=0m²+4m-m-4=0m(m+4)-1(m+4)=0(m-1)(m+4)=0Therefore m=1 or m=-4PLEASE MARK AS BRAINLIEST IF HELPFUL!!!Regards07161020Ace