Math, asked by 211244, 6 months ago

find the value of m for which
4/7^3 *4/7^-6=4/7^2 m-1

Answers

Answered by MAMohamedAli
0

Answer:

m = 2.5

Step-by-step explanation:

(4/7)³ × (4/7)^(-6) = (4/7)^[2(m-1)]

3 + (-6) = 2(m-1)  {base in all characters are equal}

3 -6 = 2m -2

3 = 2m -2

2m -2 = 3

2m = 3 +2

m = 5/2

m = 2.5

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