Question

find the value of m for which 5x²-3x+m=0has equal roots
​

Answer 1

Answer:

$\boxed{\text{Answer: m = 0.45}}$

Step-by-step explanation:

$\text{For roots to be equal, D = }\frac{b^2 - 4ac}{2a} \text{ must equal 0.}\\\\\text{In this case, a = 5, b = -3 and c = m}\\\\\text{Hence, D = }\frac{(-3)^2 - 4 \text{ x } 5 \text{ x } m}{2 \text{ x } 5} = 0\\\\\frac{9 - 20m}{10} = 0\\\\9 - 20m = 0\\\\20m = 9\\\\m = \frac{9}{20}\\\\\\\boxed{\text{Answer: m = 0.45}}$

Hope it helps! If it does, please mark it brainliest! Thanks :D

Answer 2

Answer:

m=0.45

Step-by-step explanation:

5x.sq-3x+m

D=0

D= b sq -4ac

0=(-3)sq- 4(5)(m)

0=9-20m

20m=9

m=0.45