Math, asked by kiranjit63, 2 months ago

find the value of m for which 6^m÷6^-4 = 6^8​

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Answers

Answered by prasadanand76
2

Answer:

 {6}^{m}  \div  {6}^{ - 4}  =  {6}^{8}

According to the Laws of Exponents.

 {a}^{m}  \div  {a}^{n}  =  {a}^{m - n}

 {6}^{m - ( - 4)}  =  {6}^{8}

 {6}^{m + 4}  =  {6}^{8}

Now, Comparing Exponents.

m+4=8

m=8-4

m=4

So, The answer to your question is 4.

Answered by XxLovingBoyxX
6

Answer:

Hii,

Step-by-step explanation:

Answer:

{6}^{m} \div {6}^{ - 4} = {6}^{8}6

m

÷6

−4

=6

8

According to the Laws of Exponents.

{a}^{m} \div {a}^{n} = {a}^{m - n}a

m

÷a

n

=a

m−n

{6}^{m - ( - 4)} = {6}^{8}6

m−(−4)

=6

8

{6}^{m + 4} = {6}^{8}6

m+4

=6

8

Now, Comparing Exponents.

m+4=8

m=8-4

m=4

Hope this will help you...

I hope my earlier answer will also help you...

# XxLovingBoyxX ❤️

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