Math, asked by prashantzod16, 8 months ago

Find the value of 'm' for which the given quadratic equation has real and equal roots (m-1)x²-2(m+1)x+9=0. ​

Answers

Answered by muskan610
1

Answer:

m=2, m=5

Step-by-step explanation:

b²-4ac =0

because it has real and equal roots.

Answered by pinky345
3

hence m= 2 or 5

for (m-1)x^2 - 2(m+1)X +9

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