Find the value of m for which the points (7, 2), (5, 1) and (3, m) are collinear.
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Answer: Now if these points are collinear then,
, 7/2×5/1×3/m×7/2..(1)
Now do cross multiply of 1
Now, 1/2(7×1+5×m+3×2) -(5×2+3×1+7×m) =0
Now, (7+5m+6) -(10+3+7m) =0
Now, 13+5m-13-7m=0
, 13-13+5m-7m=0
-2m=0
m=2
Step-by-step explanation:
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