Question

find the value of m if 2^11 ÷ 2^5 = 2^-3 * 2^2m-1​

Answer 1

Answer:

2^11 - 5 = 2^ -3 +2m- 1

2^6 = 2^ -4 +2m

Bases are same,then exponent on both sides will be equal.

6= -4 + 2m

2m= 6+4

2m = 10

m=10/2

m=5

Answer 2

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$\huge\tt\red{\bold{\underline{\underline{❥Question᎓}}}}$find the value of m if 2^11 ÷ 2^5 = 2^-3 * 2^2m-1

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According to the Question:-

$⟹\frac{ {2}^{11} }{ {2}^{5} } = \frac{ {2}^{ - 3} }{ {2}^{2m - 1} }$

Here ,all values are in divide form with same base say 2 so power gets substract:-

$⟹{2}^{11 - 5} = {2}^{ - 3 - (2m - 1)}$

$⟹{2}^{6} = {2}^{ - 3 - 2m + 1}$

$⟹ {2}^{6} = {2}^{ - 1 - 2m}$

Here ,base is same on both sides so 2 get cancelled

$⟹6 = - 1 - 2m$

$⟹6 + 1 = - 2m$

$⟹- 2m = 7$

$\red{m = - \frac{2}{7}}$

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