Question

find the value of m,if (2m+1)x² -(2m+1)X + (2m+1)=0 has equal roots​

Answer 1

Step-by-step explanation:

∵ It has equal roots,

b²-4ac=0

here,

b= -(2m+1)

a= 2m+1

c= 2m +1

So,

(2m-1)² - 4(2m+1)(2m+1)= 0

(2m-1)² = 4(2m+1)²

4m² - 4m + 1 = 4(4m² + 4m +1)

4m² - 4m + 1 = 16m² + 16m + 4

16m²-4m² +16m-4m +4-1=0

12m²+12m+3=0

dividing by 3,

4m²+4m+1=0

m= -b±√b²-4ac/2a

   = -4±√16-16/2x4

   = -4±√0/8

∴m= -4 +0/8 = -1/2

Answer 2

Answer:

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