find the value of m,if (2m+1)x² -(2m+1)X + (2m+1)=0 has equal roots
Answers
Answered by
6
Step-by-step explanation:
∵ It has equal roots,
b²-4ac=0
here,
b= -(2m+1)
a= 2m+1
c= 2m +1
So,
(2m-1)² - 4(2m+1)(2m+1)= 0
(2m-1)² = 4(2m+1)²
4m² - 4m + 1 = 4(4m² + 4m +1)
4m² - 4m + 1 = 16m² + 16m + 4
16m²-4m² +16m-4m +4-1=0
12m²+12m+3=0
dividing by 3,
4m²+4m+1=0
m= -b±√b²-4ac/2a
= -4±√16-16/2x4
= -4±√0/8
∴m= -4 +0/8 = -1/2
Answered by
0
Answer:
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