Find the value of m if 2square m ÷ 2square -4 =4
Answers
Answer:
Step-by-step explanation:
Let a be the first term of a given AP and d be the common difference of given AP.
We have to find the value of common difference d
We are given that the (m+2)^{th}(m+2)
th
term of an AP is (m+2)^2-m^2(m+2)
2
−m
2
a_{m+2}=(m+2)^2-m^2a
m+2
=(m+2)
2
−m
2
We are using formula
a_n=a+(n-1)da
n
=a+(n−1)d
Wherea_n=n^{th}a
n
=n
th
term of an AP
n=Total number of terms in an AP
d= Common difference
a= First term of an AP
Applying this formula we get the value of common difference
Therefore, (m+2)^2-m^2=a+(m+2-1)d(m+2)
2
−m
2
=a+(m+2−1)d
(m+2-m)(m+2+m)=a+(m+1)d(m+2−m)(m+2+m)=a+(m+1)d
Using identity :a^2-b^2=(a+b)(a-b)a
2
−b
2
=(a+b)(a−b)
(2m+2)\times2=a+(m+1)d(2m+2)×2=a+(m+1)d
4m+4-a=(m+1)d4m+4−a=(m+1)d
d=\frac{4m+4-a}{m+1}d=
m+1
4m+4−a
Hence, the common difference, d=\frac{4m+4-a}{m+1}
m+1
4m+4−a
Answer:
4 m +4-a
Step-by-step explanation: