Find the value of m, if 2x²+mx²+11x+m+3 is exactly divisible by 2x-1.
Pleeeeeeeeeeeeeas........ answer. It's very urgent!
AcharyaVII:
Confusing
Answers
Answered by
3
according to me the ans must be :
p(x)=2x-1
x=1/2
=2x^2+mx^2+11x+m+3
=2*(1/2)^2+m*(1/2)^2+11*1/2+m+3
=2*1/4+m*1/4+11/2+m+3
=1/2+m/4+11/2+m+3
=(2+m+22+4m+3)/4=0
=[5m+27]/4=0
=m=(-27*4)/5
=m=-21.6
this might be the and according to me
p(x)=2x-1
x=1/2
=2x^2+mx^2+11x+m+3
=2*(1/2)^2+m*(1/2)^2+11*1/2+m+3
=2*1/4+m*1/4+11/2+m+3
=1/2+m/4+11/2+m+3
=(2+m+22+4m+3)/4=0
=[5m+27]/4=0
=m=(-27*4)/5
=m=-21.6
this might be the and according to me
Well.... Try to answer it in decimals.
I'm in Bhavans, Hyderabad.
well thats gr8..
In which school are you?
my ans is in decimal itself that's -21.6...i m in tagore senior secondary high school thts in delhi
Sorry! answer it fractions not decimals
in fraction the ans is -108/5
what?
Once check it properly.
no idea
Answered by
2
Answer:
-7
Step-by-step explanation:
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