Question

Find the value of m if HCF of 65 and 117 is expressible in the form 65m - 117 . Pls answer by full method pls

Answer 1

Hey there !!
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HCF of 65 and 117

65 > 117

117 = 1 × 65 + 52
65 = 1 × 52 + 13
52 = 4 × 13 + 0

HCF ( 65 , 117 ) = 13

Now. 65m – 117 = 13

=> 65m = 117 + 13

=> 65m = 130

=> m = 130 / 65

=> m = 2
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Answer 2

Heya.....^_^

Here's ur ans. ⤵

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H.C.F (65, 117)

Using Euclid's Division Lemma,

65 < 117

Therefore

117 = 65×1+52

Since remainder isn't 0 , this process will be continued until the remainder become 0

65 = 52×1 + 13

↪ 13 = 13×1 + 0

Hence , (HCF) = 13

Now , ⬇

↪ 65m -117 = 13

65m = 13+117
65m= 130
m = 130/65
✡✡. m = 2. ✡✡

◾◾Hope it helps◾◾