Question

find the value of m if the equation has real and equal roots : x2 - (m + 2 ) x + (m + 5) = 0

Answer 1

Step-by-step explanation:

real and equal roots means that the determinant will be equal to zero. SO,

b^2 - 4ac = 0

b = (m+2)

a = 1

c = (m+5)

so put these values in above equation,

(m+2)^2 - 4 × 1 × (m+5) = 0

m^2 + 4 + 4m - 4m - 20 = 0

m^2 - 16 = 0

m^2 = 16

m = +4 , -4

Hope it helps you