Question

Find the value of 'm', if the following equation
has equal roots :
(m - 2)r - (5 + m)x + 16 = 0​

Answer 1

Answer:

Given the e question have equal roots

then b^2-4ac=0

Answer 2

Answer:

Step-by-step explanation:

The equation has real roots.

Therefore,

d=0

(m-2)x^2+(5+m)x+16=0

It represents the equation ax^2+bc+c=0

a=m-2,b=m+5,c=16

d=0

b^2-4ac=0

(m+5)^2-4*(m-2)*16=0

m^2+10m+25-64m+128=0

m^2-54m+153=0

m^2-3m-51m+153=0

m(m-3)-51(m-3)=0

(m-51)(m-3)=0

m-51=0. Or m-3=0

m=51. Or. m=3