Question

Find the value of 'm', if the point (4,2m-1) lies on the graph of the equation 3x+5y+3=0

Answer 1

Hey



The equation given is :-


3x + 5y + 3 = 0


A point P ( 4 , 2m- 1 ) lies on this graph .


It will he possible only when if we put the value if x and y from the point P and the equation will turn to 0 .


So ,

x = 4

y = 2m - 1


Now ,

putting values of x and y ,

we get


3x + 5y + 3 = 0 .


3 ( 4 ) + 5 ( 2m - 1 ) + 3 = 0


=> 12 + 10m - 5 + 3 = 0


=> 12 - 2 + 10m = 0


=> 10 + 10m = 0


=> 10 m = - 10


=> m = - 1


thanks :)